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James Harden will play for Steph Curry in the All-Star Game

Photo by Andrew D. Bernstein/NBAE via Getty Images
Photo by Andrew D. Bernstein/NBAE via Getty Images
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James Harden will join Stephen Curry in this year’s All-Star game.

Tonight, it was announced that Steph Curry chose James Harden to be on his team for the All-Star game in Los Angeles.

With Steph having the second pick in the draft, it is likely that he chose the Beard there. However, Curry did hint a little bit in the interview after the draft that Harden was chosen later.

It is assumed that LeBron James took Kevin Durant with the first pick, as most everyone expected him to do. Wouldn’t it have been great if he chose Harden, though?

Let’s look at the full teams for those of you who haven’t seen it yet!

Team Curry

Here is a look at the full team chosen by Steph Curry:

#TeamStephen ? pic.twitter.com/PEsvGrVwYJ

— NBA on TNT (@NBAonTNT) January 26, 2018

Of course, Steph took two of his teammates from the Warriors. That should be good for the chemistry of the squad as they look to beat Team LeBron.

One oddity, though, is that Curry took 3 centers in the draft. Joel Embiid will start while Al Horford and Karl-Anthony Towns will come off the bench. I wonder how that will work out for them! Look for Horford to potentially play some power forward during the contest.

Team LeBron

Here is a look at the full team chosen by LeBron James.

#TeamLeBron ? pic.twitter.com/Drn0lxJN4j

— NBA on TNT (@NBAonTNT) January 26, 2018

Both of the All-Star big men from New Orleans will be joining LeBron on his squad. I wonder why Curry didn’t choose one of them!

Last year’s MVP Russell Westbrook was also chosen by LeBron. Kevin Love, his teammate, will join him too.

During the interview, Curry said that he definitely chose Giannis Antetokoumpo so that he wouldn’t dunk on him like last year. If Harden was not chosen at No. 2, then he was probably chosen at No. 4. Would LeBron have chosen Kyrie Irving over the Beard?

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Next: Why Harden and Paul have worked well together

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